Mailing Lists Statistics
Another problem of statistics.?
The sales company to sell stereo Webster expensive in the mall. The table below Frequency distribution of number of orders received per day by this company during the last 100 days. number of orders received per day 2 3 4 5 6 days 12 21 34 19 14 a. build a table of probability distribution of the number of orders received per day. Draw a graph of the probability distribution. B. is the probability that contained in the table in Part A. exact or approximate probabilities of different outcomes? Explain. C. Let x = the number of orders received on a given day. Find the following probabilities: 1. P (x = 3) 2. P (x> = 3 O) 3. P (2 <or = x <or = 4 4). P (x <4)
Dear Stacy, it is not a problem well built, but this is probably not your fault. Part (a) depends on the decisions of the distribution. For example, you can use any thing as a lognormal distribution, and use data to estimate its parameters. However, let's be simplistic and that the probabilities can be approximated by maximum likelihood, if the frequency of observations, they represent our best estimate of the probability. (Understanding the problem with that, because it says there is no possibility of receiving at least two orders of six or more, which could cause problems if important decisions based on this approach.) As for (a): The figure and estimates of the probability <| 0.00 (ie, <0 control) 0 | 0.00 1 * | * * * * * * * * * * * 0.12 3 | * * * * * * * * * * * * * * | * 2 * 0.00 * * * * | * * * * * * * * * * * * * * * * * * * * * * * * 4 0.21 * * * * * * * * * * 0.34 5 | * * * * * * * * * * * * * * * * * * * | * * * * * * * * * * * * * 6 * 0.19 0.14 7 | 0.00> | 0.00 (ie> 7 orders) (b) Approx. Explanation given above. It basically says that we have seen in the past completely determines the distribution of outcomes that we expect to see in the future. It is a great leap to make because it was found than 100 days. (C) (1) P (x = 3) = 0.21. (2) P (x> = 3) = P (x = 3) + P (x = 4) + P (X = 5) + P (x = 6) + P (x = 7) + P (x> 7) = 1 – (P (x <0) + P (x = 0) + P (x = 1) + P (x = 2)) = 0.88. (3) P (2 <= x <= 4) = P (x = 2) + P (x = 3) + P (x = 4) = 0.12 + 0.21 + 0.34 = 0.67. (4) P (x <4) = P (x <0) + P (x = 0) + P (x = 1) + P (x = 2) + P (x = 3) = 0.33.
windows mailing lists,windows mailing list,winery mailing l